Content: Zadacha44-2022.docx (41.61 KB)
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Task 44 A closed tank with oil p = 900 kg / m3 is divided by a flat partition having a square flap with side a = 1m. The pressure above the oil in the left part of the tank is determined by the reading of the pressure gauge Rm = 20 kPa, and in the right – by the reading of the vacuum gauge Rvak = 30 kPa.
Determine the magnitude of the resultant force of oil pressure on the square flap and the displacement of its center of pressure relative to the center of gravity of the site.
The solution is made in the Word editor with a set of formulas. The task is performed as part of the control work on hydraulics. After payment, we guarantee to receive a file with this task. It is possible to perform according to your tasks.
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